(n^2+4+2n)(-3n+2)=0

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Solution for (n^2+4+2n)(-3n+2)=0 equation: 


Simplifying
(n2 + 4 + 2n)(-3n + 2) = 0

Reorder the terms:
(4 + 2n + n2)(-3n + 2) = 0

Reorder the terms:
(4 + 2n + n2)(2 + -3n) = 0

Multiply (4 + 2n + n2) * (2 + -3n)
(4(2 + -3n) + 2n * (2 + -3n) + n2(2 + -3n)) = 0
((2 * 4 + -3n * 4) + 2n * (2 + -3n) + n2(2 + -3n)) = 0
((8 + -12n) + 2n * (2 + -3n) + n2(2 + -3n)) = 0
(8 + -12n + (2 * 2n + -3n * 2n) + n2(2 + -3n)) = 0
(8 + -12n + (4n + -6n2) + n2(2 + -3n)) = 0
(8 + -12n + 4n + -6n2 + (2 * n2 + -3n * n2)) = 0
(8 + -12n + 4n + -6n2 + (2n2 + -3n3)) = 0

Combine like terms: -12n + 4n = -8n
(8 + -8n + -6n2 + 2n2 + -3n3) = 0

Combine like terms: -6n2 + 2n2 = -4n2
(8 + -8n + -4n2 + -3n3) = 0

Solving
8 + -8n + -4n2 + -3n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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